Repdigits base b as products of two Lucas numbers

dc.contributor.author	Erduvan, F. and Keskin, R. and Şiar, Z.
dc.date.accessioned	2021-04-08T12:06:31Z
dc.date.available	2021-04-08T12:06:31Z
dc.date.issued	2020
dc.identifier	10.2989/16073606.2020.1787539
dc.identifier.issn	16073606
dc.identifier.uri	https://www.scopus.com/inward/record.uri?eid=2-s2.0-85087830086&doi=10.2989%2f16073606.2020.1787539&partnerID=40&md5=54e48d48817bc8a28974a4c43a4618ce
dc.identifier.uri	http://acikerisim.bingol.edu.tr/handle/20.500.12898/3984
dc.description.abstract	Let (Ln) be the sequence of Lucas numbers defined by L 0 = 2, L 1 = 1, and Ln = L n−1 + L n−2 for n ≥ 2. Let 0 ≤ m ≤ n and b = 2, 3, 4, 5, 6, 7, 8, 9. In this study, we show that if LmLn is a repdigit in the base b and has at least two digits, then LmLn ∈ {3, 4, 6, 7, 8, 9, 12, 14, 16, 18, 21, 28, 36, 54, 121, 228}. Furthermore, it is shown that if Ln is a repdigit in the base b and has at least two digits, then (n, b) = (2, 2), (3, 3), (4, 6), (4, 2), (6, 5), (6, 8). Namely, L 2 = 3 = (11)2, L 3 = 4 = (11)3, L 4 = 7 = (11)6 and L 4 = 7 = (111)2, L 6 = 18 = (33)5, L 6 = 18 = (22)8. © 2020, © 2020 NISC (Pty) Ltd.
dc.language.iso	English
dc.source	Quaestiones Mathematicae
dc.title	Repdigits base b as products of two Lucas numbers

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